我們都知道且經(jīng)常用到 unsigned 關(guān)鍵字,但有沒有想過,與此對應(yīng)的 signed 關(guān)鍵字有啥用?
int i = 0;
signed int i = 0;
這倆有區(qū)別嗎?沒區(qū)別,看起來,signed 完全是個(gè)累贅。
真的是這樣嗎?
我查閱了 C++11 的標(biāo)準(zhǔn)文檔(草稿N3690),發(fā)現(xiàn)一些端倪:
3.9.1 Fundamental types
Objects declared as characters(char) shall be large enough to store any member of the implementation's basic character set. If a character from this set is stored in a character object, the integral value of that character object is equal to the value of the single character literal form of that character. It is implementation-defined whether a char object can hold negative values. Characters can be explicitly declared unsigned or signed. Plain char, signed char, and unsigned char are three distinct types, collectively called narrow character types. A char,a signed char,and an unsigned char occupy the same amount of storage and have the same alignment requirements(3.11); that is,they have the same object representation. For narrow character types, all bits of the object representation participate in the value representation. For unsigned narrow character types, all possible bit patterns of the value representation represent numbers. These requirements do not hold for other types. In any particular implementation, a plain char object can take on either the same values as a signed char or an unsigned char; which one is implementation-defined.
標(biāo)準(zhǔn)規(guī)定的很清楚,char, signed char 和 unsigned char 是三種不同的類型。 char 會(huì)根據(jù)具體實(shí)現(xiàn)場景,而決定到底是 signed 還是 unsigned.
再看看 C11 的標(biāo)準(zhǔn)文檔(ISO/IEC 9899:201x)呢?
6.7.2 Type specifiers
Each of the comma-separated multisets designates the same type, except that for bit-fields, it is implementation-defined whether the specifier int designates the same type as signed int or the same type as unsigned int.
看來,bit-fields (位域) 也存在同樣的問題。(位域的概念可能也有點(diǎn)偏,經(jīng)常寫比較底層的接口或協(xié)議童鞋應(yīng)該熟悉,可參考這里)
結(jié)論
在 C/C++ 中,signed 關(guān)鍵字絕大多數(shù)情況下都是累贅,但對于上述所言的兩種情況,即在 char 與 bit-fields 的使用過程中,還是有比較隱晦的作用的。
給自己提個(gè)醒,總是好的。