這題因為限定了4位數(shù)，所以只考慮了4位數(shù)的情況，吃點分享一個大小寫轉(zhuǎn)換的源碼，里面有不限位數(shù)的情況，當時調(diào)試的很痛苦，思想差不多。
void iConvert(int digit)
{
char a[5][10] = {"千","百","十","","零"};
char b[11][10] = {"零","一","二","三","四","五","六","七","八","九","十"};
char result[50] = {'/0'};
int A[4] = {};
for(int i=3;i>=0;i--)
{
A[i] = digit % 10;
digit = int(digit/10);
}
printf("%d,%d,%d,%d/n",A[0],A[1],A[2],A[3]);
int foundZero = 0;
for(int i = 0 ;i<4;i++)
{
if(A[i]>0)
{
strcat(result,b[A[i]]);
strcat(result,a[i]);
}
if(A[i]==0 && foundZero == 0)
{
if(i!=3)//如果不是最后一位，則不追加零
{
strcat(result,a[4]);
foundZero = 1;
}
}
}
puts(result);
}
運行結(jié)果：
