URL中去除指定參數實現C#代碼
2024-09-07 17:05:32
供稿：網友
代碼如下:
#region URL中去除指定參數
/// <summary>
/// 中去除指定參數
/// </summary>
/// <param name="url">地址</param>
/// <param name="param">參數</param>
/// <returns></returns>
public static string buildurl(string url, string param)
{
string url1 = url;
if (url.IndexOf(param) > 0)
{
if (url.IndexOf("&", url.IndexOf(param) + param.Length) > 0)
{
url1 = url.Substring(0, url.IndexOf(param) - 1) + url.Substring(url.IndexOf("&", url.IndexOf(param) + param.Length) + 1);
}
else
{
url1 = url.Substring(0, url.IndexOf(param) - 1);
}
return url1;
}
else
{
return url1;
}
}
#endregion
#region "獲取頁面url"
/// <summary>
/// 獲取當前訪問頁面地址參數
/// </summary>
public static string GetScriptNameQueryString
{
get
{
return HttpContext.Current.Request.ServerVariables["QUERY_STRING"].ToString();
}
}
/// <summary>
/// 獲取當前訪問頁面地址
/// </summary>
public static string GetScriptName
{
get
{
return HttpContext.Current.Request.ServerVariables["SCRIPT_NAME"].ToString();
}
}
/// <summary>
/// 獲取當前訪問頁面Url
/// </summary>
public static string GetScriptUrl
{
get
{
return GetScriptNameQueryString == "" ? GetScriptName : string.Format("{0}?{1}", GetScriptName, GetScriptNameQueryString);
}
}
/// <summary>
/// 獲取當前訪問頁面 參數
/// </summary>
public static string GetScriptNameQuery
{
get
{
return HttpContext.Current.Request.Url.Query;
}
}
#endregion
要去除多個參數，這么使用就可以了。buildurl(buildurl(buildurl(url,param1),param2),param3)
